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3/8v^2-75=0
Domain of the equation: 8v^2!=0We multiply all the terms by the denominator
v^2!=0/8
v^2!=√0
v!=0
v∈R
-75*8v^2+3=0
Wy multiply elements
-600v^2+3=0
a = -600; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-600)·3
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{2}}{2*-600}=\frac{0-60\sqrt{2}}{-1200} =-\frac{60\sqrt{2}}{-1200} =-\frac{\sqrt{2}}{-20} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{2}}{2*-600}=\frac{0+60\sqrt{2}}{-1200} =\frac{60\sqrt{2}}{-1200} =\frac{\sqrt{2}}{-20} $
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